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Which polygon has 40 as its exterior angles?

Which polygon has 40 as its exterior angles?

Hence, the regular polygon whose exterior angle is 40∘ is a nonagon.

How many sides are there in a polygon if the sum of their interior angles is 4 140?

Each interior angle of a regular polygon = 140 deg. So each exterior angle of the regular polygon = 180-140 = 40 deg. Hence the regular polygon has 360/40 = 9 sides.

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How many sides does a polygon have if each of its interior angles measures 140 degrees?

9
What is the name of a polygon whose interior angles are each 140°? Subtract both sides by 180°n. = 9. Therefore, the number of sides is 9 (nonagon).

How many sides are there in a regular polygon if each exterior angle measures 9 degrees?

Each exterior angle of a regular polygon is 9 degrees. How many sides does the shape have? 360 degrees (around the shape) divided by 9 degrees = 40. So the shape has 40 sides.

Is it possible to have a regular polygon whose each exterior angle is 40 of a right angle?

Hence it is possible to have a regular polygon whose each exterior angle is 40\% of a right angle.

How many sides a regular polygon has whose each exterior angle is 45 degree?

8
Explanation: Sum of exterior angle of any polygon is 360o . As each exterior angle is 45o , number of angles or sides of the polygon is 360o45o=8 .

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What is the sum of 2 adjacent interior angles of a regular 40 sided polygon?

In geometry, a tetracontagon or tessaracontagon is a forty-sided polygon or 40-gon. The sum of any tetracontagon’s interior angles is 6840 degrees.

How do you find the interior and exterior angles of a polygon?

The formula for calculating the size of an interior angle is: interior angle of a polygon = sum of interior angles ÷ number of sides. The sum of exterior angles of a polygon is 360°. The formula for calculating the size of an exterior angle is: exterior angle of a polygon = 360 ÷ number of sides.

What kind of polygon is measured by 40 degrees?

In geometry, a tetracontagon or tessaracontagon is a forty-sided polygon or 40-gon. The sum of any tetracontagon’s interior angles is 6840 degrees….Tetracontagon.

Regular tetracontagon
A regular tetracontagon
Type Regular polygon
Edges and vertices 40
Schläfli symbol {40}, t{20}, tt{10}, ttt{5}

What is the sum of the exterior angles of a 40 Gon?

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A regular polygon with an exterior angle measure of 40 degrees has nine sides. Every polygon’s exterior angle sum equals 360. So 360/40 equals nine.

Is it possible to have a regular polygon if each of its exterior angle is 50 degree?

N = 360/50 = 7.2 [Number of sides of polygon] 7.2 is not an integer. So, it is not possible to have a regular polygon whose each exterior angle is 50°.