How many 4 digits odd numbers can be formed if no digit can be repeated?
Table of Contents
- 1 How many 4 digits odd numbers can be formed if no digit can be repeated?
- 2 How many four-digit numbers are there in which all the digits are odd?
- 3 How many 4 digit odd numbers can be formed from the digits 12345?
- 4 How many 4 digit numbers are there which are odd and have distinct digits from 0 to 8?
- 5 How many distinct choices are there in 5 odd numbers?
How many 4 digits odd numbers can be formed if no digit can be repeated?
How many four-digit odd numbers do not use any digit more than once? The answer is C, 2240. Explanation from the book makes more sense now that I’ve thought about it a bit more.
How many 4 digit odd numbers can be formed using the digits 0 1 2 and 3 only if the repetition of the digit is not allowed?
As stated in the title above: How many 4-digit odd numbers can be formed using the digits 0, 1, 2 and 3 only if the repetition of the digit is not allowed? I already have the answer for this and it is 8.
How many four-digit numbers are there in which all the digits are odd?
Total no. of 4 digit numbers such that sum of the digits is odd [Answer:4500]
How many odd four-digit numbers with all of the digits different can be formed from the digits 0 to 7 if there must be a 4 in the number?
How many odd 4 digit numbers can be formed from the digits 0 through 7 if there must be a 4 in the number and numbers can’t repeat? The provided answer is 320…
How many 4 digit odd numbers can be formed from the digits 12345?
The answer is 180 four-digit odd numbers.
What is the 4 digit odd number?
Solution : The smallest 4-digit number is 1000 (which is even). Its successor is 1001 which is odd.
How many 4 digit numbers are there which are odd and have distinct digits from 0 to 8?
Hence 4536 is the number of possible arrangements of four distinct digit numbers.
How many 4-digit numbers are there with only odd digits?
If you are NOT allowed to repeat digits, the answer would be 5x4x3x2 = 120 distinct choices. Assuming you are looking for the number of 4-digit numbers having only odd digits: Each of the 4 digits can be one of [1, 3, 5, 7, 9] = 5 choices. Therefore, there are 5*5*5*5 = 625 such 4-digit numbers. The smallest is 1111 and the largest is 9999.
How many distinct choices are there in 5 odd numbers?
There are 5 odd digits (1, 3, 5, 7, 9). If you are allowed to repeat digits, this would give you five choices for each digit. The answer would therefore be 5x5x5x5 = 625 If you are NOT allowed to repeat digits, the answer would be 5x4x3x2 = 120 distinct choices.
Why is the ones digit half of the thousands digit?
The reason it’s not merely half is because, by picking the thousands digit first, we restrict the ones digit in different ways: if we select an odd thousands digit (of which there are three), there are four legal choices for the ones digit, but if we select an even thousands digit (of which there are two), there are only three.