How many 5 digit number can be made using the digits of the number?

Repetition of digits is allowed. ∴ Each place out of unit, 10th, 100th and 1000th can be filled in 5 ways. Total numbers =4×5×5×5×5=2500.

How many five digit numbers are possible if the leftmost digit Cannot be zero?

2 Answers By Expert Tutors You have five decimal places. The first four have 10 possibilities and the fifth has nine, so it would be 10x10x10x10x9- 90,000.

How many 5 digit numbers can make by starting with 5 without repeating the number from 0 to 5?

Step-by-step explanation: If we subtract these 10,000 ways from the overall 1,00,000 ways, we are left with 90,000. Therefore, there are 90,000 unique 5-digit numbers possible. Thank You!

How many 5-digit numbers can be formed using (0-9)?

How many 5-digit numbers can be formed using (0-9)? You can have up to 10 combinations for each digit, times the number of… Numbers you want. The trick is to realize that a number can not start with a zero! Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number.

How do you choose the first two digits of 012?

There are nine possible first digits, because numbers beginning in 0 drop the 0, so 012 is really just 12, a two digit number. The first digit must be 1 thru 9, nine possible digits. The second digit can be any of the nine digits left after you take the first digit out of the pool of choices. So 9*9 ways to chose the first two digits.

How many combinations can you have for a 5 digit number?

You can have up to 10 combinations for each digit, times the number of… Numbers you want. The trick is to realize that a number can not start with a zero! Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number.

How many possible groups of 5 are there with 8 digits?

You have 8 digits. You’re arranging those 8 numbers into all possible groups of 5. Since order matters here, this is a permutation problem. 8 P 5 = P 5 8 = 8! ( 8 − 5)! = 8! 3! = 8 ∗ 7 ∗ 6 ∗ 5 ∗ 4 ∗ 3! 3! Now, an easy way to think of it instead of remembering this formula is as follows: You have 8 digits and 5 slots.