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How many memory locations can be addressed by 20 address lines?

How many memory locations can be addressed by 20 address lines?

For example, an 8-bit-byte-addressable machine with a 20-bit address bus (e.g. Intel 8086) can address 220 (1,048,576) memory locations, or one MiB of memory, while a 32-bit bus (e.g. Intel 80386) addresses 232 (4,294,967,296) locations, or a 4 GiB address space.

How much memory can be addressed with 15 address lines?

13.6 Memory addressing size

Address bus size Addressable memory (bytes)
12 4K
13 8K
14 16K
15 32K

How many memory locations can be addressed using 10 bit address?

1024 memory locations
Notice that with ten address lines you can address the magic number of 1024 memory locations, and this is the closest you can get to 1000 using this system – hence 1K = 1024.

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How many bits are required for the addressing of 16 memory locations?

Sixteen address lines will address 64K bytes. If you count in binary (which computers always do) and limit yourself to 16 binary columns, you can count from 0 to 65,535. (The colloquial ”64K” is shorthand for the number 66,536.)

How many memory locations are addressed using 18 address bits?

How many memory locations are addressed using 18 address bits? Explanation: For n address bits, the memory location will consist of 2n bits. Using 18 address bits, 218 = 262,144 (= 256 K) words are addressed.

How many address and data lines will be there for a 16M 32 memory system?

d. None of the above Correct solution is (c). Since there are 16M words, the number of address lines will be 24, since 224 = 16M. Also since the word size is 32 bits, the number of data lines will also be 32.

How many memory locations can be accessed with the help of 16 address lines?

If an address bus for a given computer has 16 lines, what is the maximum amount of memory it can access? – Quora. The number of memory words addressed on a bus is 2 to the power of the width of the address bus, in this case 16. So 2 to the power of 16 is 65,536, commonly referred to as 64K.

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How many different memory locations can be accessed using 12 bits?

4096 locations
Each memory location is one byte, while the address is 12-bit, with the capability to address up to 4096 locations.

How many locations are addressed using 18 address bits?

How many bits of storage does a memory system contain if it has a 16k address space and is 8 bit addressable?

You have to use word size in calculations as well. The answer is 64 KB. You can address 2^16 words and each word is 8 bit (= 1 byte). Therefore it is 64 KB.

How many address bits are needed for all of memory?

Therefore 32 bits are required to uniquely address each 32-bit word. Therefore 34 bits are required to uniquely address each byte. . Therefore 28 address bits are needed.

How many address bits are required for a 1024 * 8 memory?

Or 1024*8 gives 8192, or 2^13. so 13 bits. If it ain’t a 1024 bits multiplied by 8 bits, or there are 1024 arrays of each size of 8 bit, then 1024 arrays, so 10 bits of addresses will do it.

What is the maximum number of addresses in RAM?

If there are just 2 bits in the address, then there can only be 4 addresses, viz. If 3 bits are allowed in the address, then we can have maximum 8 addresses: So, if we have n bits to store an Address (n-bits in Address Register) or n-wires to transfer the address (Address bus of size 10), then we can have RAM of 2 n addresses.

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How many values can be stored in a memory address?

Memory addresses are numbers too, so on a 32-bit CPU the memory address consists of 32 bits. Now think about this: if you have one bit, you can save two values on it: 0 or 1. Add one more bit and you have four values: 0, 1, 2, 3. On three bits, you can save eight values: 0, 1, 2… 6, 7.

How many bits are in a 32 bit memory address?

Memory addresses are numbers too, so on a 32-bit CPU the memory address consists of 32 bits. Now think about this: if you have one bit, you can save two values on it: 0 or 1. Add one more bit and you have four values: 0, 1, 2, 3.

How many memory locations can be addressed in 16 kilo bytes?

Aroun 16 Kilo Bytes of memory locations can be addressed. You can calculate the number of memory locations by using this formula: No. of Memory locations = 2^n, where n = number of address lines.